Tìm x ∈ N biết: (80-({4.5^2}-{3.2^3}) = {2^{10;}} – left( {x – 4} right).)

Ta có:

(begin{array}{*{20}{l}}
{80- left( {{{4.5}^2};- {{3.2}^3}} right) = {2^{10}};- left( {x- 4} right)}\
{begin{array}{*{20}{l}}
{80 – left( {4.25 – 3.8} right) = {2^{10}} – left( {x – 4} right)}\
{80 – left( {100 – 24} right) = {2^{10}} – left( {x – 4} right)}\
{80- 76 = {2^{10}};- left( {x- 4} right)}
end{array}}\
{begin{array}{*{20}{l}}
{4 = {2^{10}};- left( {x- 4} right)}\
{{2^{10}} – left( {x – 4} right) = 4}
end{array}}\
{x- 4 = {2^{10}};- 4;}\
{x = {2^{10}};- 4 + 4 = {2^{10}}; = 1024}
end{array})