Câu hỏi:
Tính (mathop {lim }limits_{x to {3^ + }} dfrac{{left| {x – 3} right|}}{{3x – 9}}) bằng?
Lời giải tham khảo:
Đáp án đúng: C
(mathop {lim }limits_{x to {3^ + }} dfrac{{left| {x – 3} right|}}{{3x – 9}} ) (= mathop {lim }limits_{x to {3^ + }} dfrac{{x – 3}}{{3x – 9}}) ( = mathop {lim }limits_{x to {3^ + }} dfrac{{x – 3}}{{3left( {x – 3} right)}} ) (= mathop {lim }limits_{x to {3^ + }} dfrac{1}{3} = dfrac{1}{3})
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