Em hãy tìm giới hạn (mathop {lim }limits_{x to 2} dfrac{{2{x^2} – 5x + 2}}{{{x^3} – 8}})

(begin{array}{l}mathop {lim }limits_{x to 2} dfrac{{2{x^2} – 5x + 2}}{{{x^3} – 8}}\ = mathop {lim }limits_{x to 2} dfrac{{left( {x – 2} right)left( {2x – 1} right)}}{{left( {x – 2} right)left( {{x^2} + 2x + 4} right)}}\ = mathop {lim }limits_{x to 2} dfrac{{2x – 1}}{{{x^2} + 2x + 4}}\ = dfrac{{2.2 – 1}}{{{2^2} + 2.2 + 4}} = dfrac{1}{4}end{array})